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Can you solve it (Multiply) (4 – 3i)(-7 – 2i)?
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-23 + 13i
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22i
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-34 + 13i
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None of the above
That's Correct!
It's Wrong!
To solve the given multiplication, we can use the FOIL method. Multiplying the first terms of each binomial gives us (4)(-7) = -28. Multiplying the outer terms gives us (4)(-2i) = -8i. Multiplying the inner terms gives us (-3i)(-7) = 21i. Multiplying the last terms gives us (-3i)(-2i) = $$6i^2$$. Simplifying, we have -28 - 8i + 21i + $$6i^2$$. Since $$i^2$$ is equal to -1, we can substitute it in the expression to get -28 - 8i + 21i + 6(-1). Combining like terms, we have -28 + 13i - 6, which simplifies to -34 + 13i. Therefore, the correct answer is -34 + 13i.
